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IGCSE Chemistry: Cambridge 0620 tutoring, Malaysia

Oxidation Number – IGCSE Chemistry Definition

IGCSE Chemistry definition of oxidation number: a number assigned to an atom showing its degree of oxidation. Covers rules, Roman numerals, and tracking redox changes.

Published by IGCSEChemistry.com.my

Chemistry teaching team: K. S. Tan (15+ years teaching IGCSE Chemistry) and Ms Yash (10+ years teaching IGCSE Chemistry) and Ms Kartini (15+ years teaching IGCSE Chemistry).

Mapped to Cambridge IGCSE Chemistry 0620 (2026–2028). Last updated 2026-08-19.

Oxidation numbers (also called oxidation states) are used to track electron transfer in redox reactions. On the 0620 syllabus (Supplement), oxidation numbers appear most often as Roman numerals in compound names (e.g. iron(III) oxide) and in determining whether oxidation or reduction has occurred.

The 0620 definition

An oxidation number is a number assigned to an atom that indicates its degree of oxidation in a compound or ion. An increase in oxidation number = oxidation. A decrease in oxidation number = reduction.

Rules for assigning oxidation numbers

RuleExamples
Elements in their natural state = 0Fe = 0, O₂ = 0, Na = 0
Simple ions = charge of the ionNa⁺ = +1, Cl⁻ = -1, Fe²⁺ = +2, O²⁻ = -2
Oxygen is usually -2In H₂O, MgO, CO₂, each O = -2
Hydrogen is usually +1In H₂O, HCl, each H = +1
Sum of oxidation numbers = overall chargeIn a neutral compound, sum = 0; in an ion, sum = charge

Using Roman numerals in names

When a metal can form more than one ion, Roman numerals specify which one:

NameMetal ionOxidation number of metal
Iron(II) chloride, FeCl₂Fe²⁺+2
Iron(III) chloride, FeCl₃Fe³⁺+3
Copper(I) oxide, Cu₂OCu⁺+1
Copper(II) sulfate, CuSO₄Cu²⁺+2
Manganese(IV) oxide, MnO₂Mn⁴⁺+4
Lead(II) bromide, PbBr₂Pb²⁺+2

Tracking redox using oxidation numbers

If the oxidation number of an atom increases during a reaction, it has been oxidised (lost electrons).

If the oxidation number decreases, it has been reduced (gained electrons).

Example: 2Na + Cl₂ → 2NaCl

  • Na: 0 → +1 (increase = oxidised)
  • Cl: 0 → -1 (decrease = reduced)

Example: CuO + H₂ → Cu + H₂O

  • Cu: +2 → 0 (decrease = reduced)
  • H: 0 → +1 (increase = oxidised)

Worked exam question

In the reaction: Fe₂O₃ + 3CO → 2Fe + 3CO₂. (a) State the oxidation number of iron in Fe₂O₃. (1) (b) State the oxidation number of iron in Fe. (1) (c) Has iron been oxidised or reduced? Explain. (1)

Mark scheme

(a) +3 [1] (each O = -2, three oxygens = -6, two irons share +6, so each Fe = +3)

(b) 0 [1] (iron is an element in its natural state)

(c) Reduced [1]; because the oxidation number decreased from +3 to 0 / iron gained electrons

Common exam mistakes

  • Confusing the sign of the oxidation number. Metals in compounds have positive oxidation numbers. Oxygen is usually -2.
  • Forgetting that elements have an oxidation number of 0. Fe, O₂, Na, and Cl₂ all have oxidation number 0.
  • Mixing up the Roman numeral naming convention. Iron(III) means the iron has a +3 oxidation number, not that there are 3 iron atoms.

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Frequently asked questions

What is an oxidation number?

An oxidation number (or oxidation state) is a number assigned to an atom in a compound or ion that indicates how many electrons it has gained, lost, or shared. It helps track which atoms are oxidised and reduced in a reaction.

What do the Roman numerals in compound names mean?

Roman numerals show the oxidation number of the metal ion. Iron(II) means Fe has an oxidation number of +2 (Fe2+). Iron(III) means Fe has an oxidation number of +3 (Fe3+).

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