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IGCSE Chemistry: Cambridge 0620 tutoring, Malaysia

Half-Equation – IGCSE Chemistry Definition

IGCSE Chemistry definition of half-equation: an equation showing the gain or loss of electrons at one electrode. Covers writing and balancing half-equations for electrolysis.

Published by IGCSEChemistry.com.my

Chemistry teaching team: K. S. Tan (15+ years teaching IGCSE Chemistry) and Ms Yash (10+ years teaching IGCSE Chemistry) and Ms Kartini (15+ years teaching IGCSE Chemistry).

Mapped to Cambridge IGCSE Chemistry 0620 (2026–2028). Last updated 2026-08-19.

A half-equation shows what happens at a single electrode during electrolysis — specifically, the gain or loss of electrons by the ions. Writing and balancing half-equations is a key Supplement skill on the 0620 syllabus. Examiners award marks separately for the correct formula, the correct number of electrons, and correct balancing.

The 0620 definition

A half-equation is an equation that shows the transfer of electrons at one electrode during electrolysis. Electrons are shown as e⁻.

Half-equations at the cathode (reduction)

Cations gain electrons. Electrons appear on the left side of the equation.

ReactionHalf-equation
Copper depositedCu²⁺ + 2e⁻ → Cu
Lead depositedPb²⁺ + 2e⁻ → Pb
Silver depositedAg⁺ + e⁻ → Ag
Hydrogen gas produced2H⁺ + 2e⁻ → H₂
Aluminium depositedAl³⁺ + 3e⁻ → Al

Half-equations at the anode (oxidation)

Anions lose electrons. Electrons appear on the right side of the equation.

ReactionHalf-equation
Chlorine gas produced2Cl⁻ → Cl₂ + 2e⁻
Bromine produced2Br⁻ → Br₂ + 2e⁻
Oxygen gas produced4OH⁻ → 2H₂O + O₂ + 4e⁻

How to write a half-equation

  1. Write the ion on one side and the product on the other
  2. Balance the atoms (you may need to double the ions for diatomic products like Cl₂)
  3. Add electrons to balance the charge
  4. Check: total charge on the left = total charge on the right

Example: chloride ions at the anode

  • Start: Cl⁻ → Cl₂ (chlorine is diatomic, so need 2 Cl⁻)
  • Balance atoms: 2Cl⁻ → Cl₂
  • Balance charge: left side = 2 x (-1) = -2. Right side = 0. Add 2e⁻ to the right.
  • Final: 2Cl⁻ → Cl₂ + 2e⁻

Worked exam question

During the electrolysis of dilute sulfuric acid: (a) Write the half-equation at the cathode. (1) (b) Write the half-equation at the anode. (2) (c) State which half-equation represents oxidation. (1)

Mark scheme

(a) 2H⁺ + 2e⁻ → H₂ [1]

(b) 4OH⁻ → 2H₂O + O₂ + 4e⁻ [1 for correct formula/products, 1 for balance]

(c) The anode half-equation [1] — because electrons are lost / appear on the right / oxidation is loss of electrons

Common exam mistakes

  • Putting electrons on the wrong side. At the cathode, electrons are gained (left side). At the anode, electrons are lost (right side).
  • Forgetting to make gaseous products diatomic. Chlorine is Cl₂ not Cl; hydrogen is H₂ not H; oxygen is O₂ not O.
  • Not balancing the charge. If you have 2Cl⁻ on the left (charge = -2) and Cl₂ on the right (charge = 0), you need 2e⁻ on the right to balance.

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Frequently asked questions

What is a half-equation?

A half-equation shows what happens at one electrode during electrolysis. It shows either the gain of electrons (reduction, at the cathode) or the loss of electrons (oxidation, at the anode). Electrons are written as e-.

How do you balance a half-equation?

Balance the atoms first, then balance the charges by adding electrons. The total charge on the left must equal the total charge on the right.

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